What Are The Penalties For Felony Drug Charges In Iowa?

Being accused of a crime is never any easy predicament to be in. This is especially true when the accused is facing a felony charge. With regards to drug crimes, the penalties associated with a drug charge could be severe, as a felony charge likely involves large quantitates of an illegal substance or an act that is severe itself.

What are the penalties for felony drug charges in Iowa? In order to face a class B felony for drug possession in the state of Iowa, which results in a penalty of not more than 50 years in prison and a fine not greater than $1,00,000, one must possess a certain amount of each drug type. This includes more than 10 grams of LSD, more than 50 grams of crack cocaine, more than 500 grams of cocaine, greater than 100 grams of PCP pure, more than 1 kilogram of PCP mixed, more than 1 kilogram of heroin, greater than 1,000 kilograms of marijuana and more than 5 kilo grams of methamphetamine amphetamine.

With regards to the possession of marijuana, the first offense can result in 6 months in jail and a fine of $1,000. A second offense is considered a serious misdemeanor, which results in similar penalties. However, a third offense is considered an aggravated misdemeanor, resulting a penalty of up to 2 years in prison and a fine up to $5,000.

With regards to drug crimes, the type and quantity in question often dictate the severity of the criminal consequences one would face if convicted. While the penalties may be harsh, it is important to understand that individuals have the right to initiate a criminal defense. This process could result in the charges being reduced and even dismissed, making it a crucial step to take.